Answer:
original is 4 & 6.
for 54 sq inch= 6 & 9 and for 96 sq inch=8 & 12
Step-by-step explanation:
Given: The length is 1.5 times the width.
so the length is, l = 1.5w ----(a)
lw = 24 =1.5w(w)
lw = 54= 1.5w(w)
lw = 96 =1.5w(w)
Further simplifying it,
1.5[tex]w^{2}[/tex]=24
1.5[tex]w^{2}[/tex]=54
1.5[tex]w^{2}[/tex]=96
so,
[tex]w^{2}[/tex] = [tex]\frac{24}{1.5}[/tex]=16
[tex]w^{2}[/tex]= [tex]\frac{54}{1.5} =[/tex]36
[tex]w^{2}[/tex]= [tex]\frac{96}{1.5} =[/tex]64
taking the square root, we get:
w = 4
w = 6
w = 8
By putting the above values in eq (a), we can find their corresponding lengths:
l = 1.5(4) = 6
l = 1.5(6) = 9
l = 1.5(8) = 12
So a few lengths could be:
(l, w)
(6,4)
(9,6)
(12,8)
Answer:
Step-by-step explanation:
Given:
Initial area, Ai = 24 in^2
First enlargement, A1 = 54 in^2
Second enlargement, A2 = 96 in^2
Length, L = 3/2 × B
Area of a rectangle = L × B
Ai = 3/2B × B
24 = 3/2 B^2
B = sqrt(16)
= 4 in
A1 = 3/2B × B
54 = 3/2 B^2
B = sqrt(36)
= 6 in
A2 = 3/2B × B
96 = 3/2 B^2
B = sqrt(64)
= 8 in
For the first enlargement,
2in : 3in
Second enlargement,
1in : 4in
