Question

7 times a number is 8 less than the square of that number. Find the negative solution.

Answer 1

Answer:

Step-by-step explanation:

x^2-8x+x-8

x(x-8)+1(x-8)

(x+1)(x-8)

The negative number is x=-1

Answer 2

The negative value of 'a' is -1 and this can be determined by forming the quadratic equation using the given data.

Given :

7 times a number is 8 less than the square of that number.

The following steps can be used in order to determine the negative solution:

Step 1 - Let the unknown number be 'a'.

Step 2 - So, the quadratic equation that represents the given situation is given below:

$7a = a^2-8$

$a^2-7a-8=0$

Step 3 - Now, determine the value of 'a' using the below calculations.

$a =\dfrac{7\pm\sqrt{49+32} }{2}$

$a = \dfrac{7\pm9}{2}$

Step 4 - So, the negative value of 'a' is given by:

$a = \dfrac{7-9}{2}$

a = -1

For more information, refer to the link given below:

https://brainly.com/question/11897796