Question

An AC generator supplies 230 V peak voltage at 210 Hz frequency. How much power is dissipated in a resistor with R = 225 Ω resistance connected to the generator?

Answer 1

Answer:

The power dissipated in a resistor is 117.54 watts.

Explanation:

Given that,

Peak voltage of the Ac generator, V = 230 V

Frequency, f = 210 Hz

Resistance, R = 225 ohms

We need to find the power dissipated in a resistor. The power generated is given by :

$P=\dfrac{V^2_{rms}}{R}$

$V_{rms}=\dfrac{V}{\sqrt{2} }\\\\V_{rms}=\dfrac{230}{\sqrt{2} } \\\\V_{rms}=162.63\ V$

So,

$P=\dfrac{162.63^2}{225}\\\\P=117.54\ W$

So, the power dissipated in a resistor is 117.54 watts. Hence, this is the required solution.