Question

Chromium reacts with oxygen gas to form chromium(III) oxide. In the balanced chemical equation for this change, what are the lowest, whole number coefficients? Match the number to the species.

Answer 1

Answer:

$Cr$=4

$O_2$=3

$Cr_2O_3$=2

Explanation:

We have to start with the formula for each compound, so:

Chromium = $Cr$

Oxygen gas= $O_2$

Chromium(III) oxide= $Cr_2O3$

Now we can step up the reaction:

$Cr~+~O_2->~Cr_2O_3$

The next step is the balancing process:

$4Cr~+~3O_2->~2Cr_2O_3$

We will have a coefficient of "4" for $Cr$ a coefficient of "3" for $O_2$ and a coefficient of "2" for $Cr_2O_3$.

Answer 2

The reaction between chromium and oxygen to form chromium(III) oxide is 4Cr + 3O2 -------> 2Cr2O3

A chemical change is often shown by a chemical reaction equation.A chemical reaction is a representation of a chemical change that occurs in a reaction vessel on paper.

When writing a chemical reaction equation, the number of atoms of each element on the right hand side of the reaction equation must be the same as the number of atoms of the same element on the left hand side of the reaction equation.

For the reaction between chromium and oxygen to form chromium(III) oxide, the reaction equation is as follows;

4Cr + 3O2 -------> 2Cr2O3

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