Answer:
Angular momentum of the system is 4.8 kg m^2/s
Explanation:
As we know that the angular momentum of the system of masses is given as
[tex]L = 2I\omega[/tex]
here we have
[tex]I = m(0.2 + 0.4)^2[/tex]
[tex]I = 3(0.6)^2[/tex]
now we also know that
[tex]\omega = \frac{v}{0.2 + 0.4}[/tex]
[tex]0.6 \omega = 2 m/s[/tex]
now we have
[tex]L = 2(2)(0.6)(2)[/tex]
[tex]L = 4.8 kg m^2/s[/tex]