Question

A piston motion moves a 25-kg hammerhead vertically down 1 m from rest to a velocity of 50 m/s in a stamping machine. What is the change in total energy of the hammerhead?

Answer 1

Answer:

31.005 KJ

Explanation:

We are given that

Mass of hammerhead=25 kg

Initial velocity,u=0

Final velocity,v=50 m/s

h=-1 m

h'=0

We have to find the change in total energy of the hammerhead.

Change in total energy=$E_2-E_1=m(u_2-u_1)+\frac{1}{2}m(v^2-u^2)+mg(h-h')$

Using the formula

Change in internal energy of hammerhead=$m(u_2-u_1)=0$

Change in total energy=$\frac{1}{2}(25)(50)^2+25\times 9.8(-1)$

Where $g=9.8m/s^2$

Change in total energy=$31005 J=\frac{31005}{1000}=31.005 KJ$

1 KJ=1000 J