Respuesta :
Answer:
See the answer below
Explanation:
Black individuals is BB.
White individuals are bb.
Homozygous black bird BB is crossed with homozygous white bird bb.
BB (Black) x bb (white) = all Bb (bluish-gray).
See the attached image for the Punnet square analysis.
![Ver imagen Oseni](https://us-static.z-dn.net/files/d11/c9516323073e715e2e27fbeeade4112d.png)
Answer: The genotype of a homozygous black bird is BB while that of a homozygous white bird is bb. The genotype of the offsprings is Bb
Explanation: A cross between a homozygous black bird (BB) and a homozygous white bird (bb) will produce four offsprings all with genotype Bb.
A homozygous black bird (BB) will manifest phenotypically as a black bird and a homozygous white bird (bb) will manifest phenotypically as a white bird while a heterozygous bird (Bb) will manifest phenotypically as bluish-gray bird.
See the attached punnet square for more information
![Ver imagen coge4eva](https://us-static.z-dn.net/files/d2c/95229a7161a18c34f205d43d7cc78d69.jpg)