Determine the units of the rate constant for all four reactions listed in the problem above, and enter the correct choices from the list below. Enter 4 letters in order (e.g. ABCD or CBED)a. mole L-1 sec-1
b. mole-1 L sec-1
c. mole2 L-2 sec-1
d. mole-2 L2 sec-1
e. None of the above.

Respuesta :

The given question is incomplete. The complete question is :

For the net reaction: [tex]2AB+2C\rightarrow A_2+2BC[/tex], the following slow first steps have been proposed.

A. [tex]2C+AB\rightarrow AC+BC[/tex]

B. [tex]2AB\rightarrow A_2+2B[/tex]

C. [tex]C+AB\rightarrow BC+A[/tex]

D. [tex]AB \rightarrow A + B[/tex]

Determine the units of the rate constant for all four reactions listed in the problem above, and enter the correct choices from the list below. Enter 4 letters in order (e.g. ABCD or CBED)

a. [tex]moleL^{-1 }sec^{-1}[/tex]

b. [tex]mole^{-1}Lsec^{-1}[/tex]

c. [tex]mole^2L^{-2}sec^{-1}[/tex]

d. [tex]mole^{-2}L^2sec^{-1}[/tex]

e. None of the above.

Answer:  A. [tex]2C+AB\rightarrow AC+BC[/tex] : [tex]mol^{-2}L^2s^{-1}[/tex]

B. [tex]2AB\rightarrow A_2+2B[/tex] : [tex]k=mol^{-1}Ls^{-1}[/tex]

C. [tex]C+AB\rightarrow BC+A[/tex] : [tex]k=mol^{-1}Ls^{-1}[/tex]

D. [tex]AB \rightarrow A + B[/tex]:  [tex]k=s^{-1}[/tex]

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

1. [tex]2C+AB\rightarrow AC+BC[/tex]

[tex]Rate=k[C]^2[AB}^1[/tex]

[tex]molL^{-1}s^{-1}=k[molL^{-1}]^2[molL^{-1}}^1[/tex]

[tex]k=mol^{-2}L^2s^{-1}[/tex]

2. [tex]2AB\rightarrow A_2+2B[/tex]

[tex]Rate=k[AB]^2[/tex]

[tex]molL^{-1}s^{-1}=k[molL^{-1}]^2[/tex]

[tex]k=mol^{-1}Ls^{-1}[/tex]

3. [tex]C+AB\rightarrow BC+A[/tex]

[tex]Rate=k[C}^1[AB]^1[/tex]

[tex]molL^{-1}s^{-1}=k[molL^{-1}]^1[molL^{-1}]^1[/tex]

[tex]k=mol^{-1}Ls^{-1}[/tex]

4. [tex]AB \rightarrow A + B[/tex]

[tex]Rate=k[AB]^1[/tex]

[tex]molL^{-1}s^{-1}=k[molL^{-1}]^1[/tex]

[tex]k=s^{-1}[/tex]

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