Question

A woman holds a 41-N weight at arm's length for 11 seconds. Her arm is 1.3-m above the ground. The work done by the woman on the weight to keep the weight steady is _____ J. Round your answer to the nearest whole number.

Answer 1

Answer:

The work done by the woman is 0.

Explanation:

Weight hold by a woman, W = 41 N

Time for which she hold the weight, t = 11 s

Her arm is 1.3-m above the ground. We need to find the work done by the woman on the weight to keep the weight steady. Work done is given by formula as :

$W=F\times d$

d is the displacement

Here, the women's hand is 1.3 m above the ground. So, there is no displacement. The work done,

W = 0 Joules

Hence, this is the required solution.