Answer: Step 2 in the given mechanism is the rate determining step
Explanation:
In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.
The intermediate reaction of the mechanism follows:
Step 1: [tex]O_3(g)\rightleftharpoons O_2(g)+O(g);\text{ (fast)}[/tex]
Step 2: [tex]O_3(g)+O(g)\rightarrow 2O_2(g);\text{(slow)}[/tex]
As, step 2 is the slow step. It is the rate determining step
Rate law for the reaction follows:
[tex]\text{Rate}=k[O_3][O][/tex]
Hence, step 2 in the given mechanism is the rate determining step