Question

The drawing shows a type of flow meter that can be used to measure the speed of blood in situations when a blood vessel is sufficiently exposed (e.g., during surgery). Blood is conductive enough that it can be treated as a moving conductor. When it flows perpendicularly with respect to a magnetic field, as in the drawing, electrodes can be used to measure the small voltage that develops across the vessel. Suppose the speed of the blood is 0.57 m/s and the diameter of the vessel is 5.4 mm. In a 0.73-T magnetic field what is the magnitude of the voltage that is measured with the electrodes in the drawing?

Answer 1

Answer:

0.00225 V = 2.25 mV

Explanation:

The voltage that is developed across the vessels is given as

E = BvL

B = magnetic field strength = 0.73 T

v = velocity of the moving conductor = velocity of blood = 0.57 m/s

L = length across which the emf develops = 5.4 mm = 0.0054 m (since the voltage to be calculated is the one developed across the vessel; that is, across the length of the diameter)

E = BvL

E = 0.73 × 0.57 × 0.0054

E = 0.00224694 V

E = 2.25 mV

Hope this Helps!!!

Answer 2

The image is missing and i have attached it;

Answer:

Magnitude of Voltage = 2.21 x 10^(-3) V

Explanation:

From the question, The blood flowing at a speed v corresponds to the moving rod, and the diameter of the blood vessel corresponds to the length L of the rod in the figure. The magnitude of the magnetic

field is B, and the measured voltage is the emf (ξ) induced by the motion. Thus, we can apply;

ξ = BvL

Diameter L =5.4mm = 5.4 x 10^(-3)m

Thus;

ξ = 0.73 x 0.56 x 5.4 x 10^(-3) = 2.21 x 10^(-3) V