Question

A solenoid that has length 30 cm, radius 1.2 cm, and 300 turns carries a current of 2.6 A. Find the magnitude of the magnetic field on the axis of the solenoid:

Answer 1

Answer:

Explanation:

length, l = 30 cm

Number of turns, N = 300

Current, i = 2.6 A

number of turns per unit length, n = N / l = 300 / 0.3 = 1000

The magnetic field due to the current carrying solenoid is

$B=\mu _{0}ni$

B = 4 x 3.14 x 10^-7 x 1000 x 2.6

B = 3.27 x 10^-3 T

B = 3.27 mT