Answer:
g(- 2) = - [tex]\frac{43}{16}[/tex]
Step-by-step explanation:
Using the rules of exponents
[tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex] and [tex]a^{0}[/tex] = 1
Given
g(x) = 5[tex]x^{-4}[/tex] - 3[tex]x^{0}[/tex], then
g(- 2) = 5[tex](-2)^{-4}[/tex] - 3[tex](-2)^{0}[/tex] = [tex]\frac{5}{(-2)^{4} }[/tex] - 3(1) = [tex]\frac{5}{16}[/tex] - [tex]\frac{48}{16}[/tex] = - [tex]\frac{43}{16}[/tex]