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Given g(x) = 5x^-4- 3xº, find g(-2). Show all intermediate steps. Write answer as a fraction in lowest
terms.

Respuesta :

Answer:

g(- 2) = - [tex]\frac{43}{16}[/tex]

Step-by-step explanation:

Using the rules of exponents

[tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex] and [tex]a^{0}[/tex] = 1

Given

g(x) = 5[tex]x^{-4}[/tex] - 3[tex]x^{0}[/tex], then

g(- 2) = 5[tex](-2)^{-4}[/tex] - 3[tex](-2)^{0}[/tex] = [tex]\frac{5}{(-2)^{4} }[/tex] - 3(1) = [tex]\frac{5}{16}[/tex] - [tex]\frac{48}{16}[/tex] = - [tex]\frac{43}{16}[/tex]

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