Respuesta :
Answer:
Using the heisenbergs uncertainty principle equation
Δx . Δp [tex]\geq[/tex] h / 4[tex]\pi[/tex]
first find the speed for 0.10% : 45 m/s / 100% = x / 0.10%
∴ Δv = 0.045 m/s
Δx [tex]\geq[/tex] 6.626×[tex]10^{-34}[/tex]/ 4×[tex]\pi[/tex]× 0.145×0.045
Δx [tex]\geq[/tex] 8.081×[tex]10^{-33}[/tex]m
Explanation:
heisenbergs uncertainty principle equation allows to find the uncertainty position (in m) where one calculates the uncertainty speed of 0.10% by simple first identifying the uncertainty speed of 100%
Answer:
Δx ≥ 8 x 10^(-29) m
Explanation:
We will solve this using Heisenberg's Uncertainty Principle which states that one cannot simultaneously measure with great precision both the momentum, and the position of a particle.
Thus, mathematically, this is expressed as
Δp ⋅ Δx ≥ h/4π
where;
Δp is the uncertainty in momentum;
Δx is the uncertainty in position;
h is Planck's constant which has a value of 6.626 x 10^(−34) m²kg/s
Furthermore, the uncertainty in momentum can be written as;
Δp = m ⋅ Δv
where Δv is the uncertainty in velocity while m is the mass of the particle.
In this question, the mass of the baseball is 0.145kg or 145g with an uncertainty in velocity of 0.1%
So, uncertainty in velocity = 0.1% x 45 = 0.045 m/s
Thus, the uncertainty in momentum will be;
Δp = 0.145kg x 0.045 m/s = 6.525 x 10^(-3) m.kg/s
Now, let's plug in the relevant data into the Uncertainty Principle equation and make Δx the subject.
Thus;
Δx ≥ (h/4π) x (1/Δp)
Δx ≥ [(6.626 x 10^(−34))/(4π)] /(1/(6.525 x 10^(-3)))
= 8.08 x 10^(-29) m
If we round to one sig fig, the uncertainty in velocity, will be
Δx ≥ 8 x 10^(-29) m