Question

A flywheel rotating at 14 rev/s is brought to rest in 8 seconds. The magnitude of the average angular acceleration of the wheel during this process is _____ rad/s2. Round your answer to the nearest tenth.

Answer 1

Answer:

The magnitude of the average angular acceleration of the wheel during this process is $11\ rad/s^2$.

Explanation:

Given that,

Initial speed of a flywheel, u = 14 rev/s = 87.96 rad/s

Finally, it comes to rest, v = 0

Time, t = 8 seconds

We need to find the magnitude of the average angular acceleration of the wheel during this process. We know that the rate of change of its angular velocity is called angular acceleration. It is given by :

$\alpha =\dfrac{\omega_f-\omega_i}{t}\\\\\alpha =\dfrac{0-87.96}{8}\\\\\alpha =-10.995\ rad/s^2$

$|\alpha |=10.995\ rad/s^2$

or

$|\alpha |=11\ rad/s^2$

So, the magnitude of the average angular acceleration of the wheel during this process is $11\ rad/s^2$. Hence, this is the required solution.