Question

A flask has a mass of 78.23 g when empty and 593.63 g when filled with water. When the same flask is filled with concentrated sulfuric acid, H2SO4, its mass is 1026.57 g. What is the density of concentrated sulfuric acid

Answer 1

Answer:

1.84 g/mL

Explanation:

If we want to calculate the density we have to keep in mind that we need the mass and the volume of the Sulfuric acid $H_2SO_4$.

$D=\frac{Mass}{Volume}$

To calculate the mass we have to substract the mass of the flask from the mass of the flask plus $H_2SO_4$, so:

$Mass~of~H_2SO_4=1026.57~g-78.23~g=948.34~g~H_2SO_4$

To calculate the volume we have to use the water information. The first step is the calculation of the mass of water:

$Mass~of~H_2O~=~593.63~g-~78.23~g=~515.4~g~H_2O$

The density of water is 1 g/mL, so we can use this value to calculate the volume of the flask:

$515.4~g~H_2O\frac{1~mL}{1~g}=~515.4~mL~H_2O$

Therfore the volume of the flask is 515.4 mL

Finally, we have to divide the mass by the volume:

$D=\frac{948.34~g}{515.4~mL}=1.84~g/mL$

The density of $H_2SO_4$ is 1.84 g/mL

Answer 2

Answer:

1840.01  kg/m³

Explanation:

From Archimedes's principle.

mass of H₂SO₄/ mass of water = Density of H₂SO₄/Density of water.

M/M' = D/D'................ Equation 1

Where M = mass of H₂SO₄, M' = mass of water, D = Density of H₂SO₄, D' = Density of water.

make D the subject of the equation

D = D'(M/M').................. Equation 2

Given: M' = 593.63-78.23 = 515.4 g = 0.5154 kg, M = 1026.57-78.23 = 948.34 g = 0.94834 kg, D' = 1000 kg/m₃

Substitute into equation 2

D = 1000(0.94834/0.5154)

D = 1840.01 kg/m³

Hence the density of concentrated sulfuric acid = 1840.01 kg/m³