Answer:
Explanation:
mass of box, m = 60 kg
distance, d = 6.2 m
force, P = 150 N
coefficient of kinetic friction, μk = 0.21
work done by the gravitational force, Wg = Force x distance x cos 90
Wg = 0 J
Work done by the normal force, Wn = force x distance x Cos 90
Wn = 0 J
Work done by the friction force, Wf = - μk mg d
Wf = - 0.21 x 60 x 9.8 x 6.2 = - 765.58 J
Work done by the applied force, Wp = P x d
Wp = 150 x 6.2 = 930 J