Answer:
a. 0.6899
b. 0.1642
Step-by-step explanation:
a. Given the probability of success is 0.94 for an expert and that the number of pairs, n=6:
-Each attempt is independent and therefore the probability of the events is calculated as:
[tex]P(A \ and \B )=P(A)\times P(B)\\\\P(6)=0.94\times0.94\times0.94\times0.94\times0.94\times0.94\\\\=0.6899[/tex]
Hence, the probability of correctly identifying the 6 matches is 0.6899
b.Given the probability of success is 0.74 for a novice and that the number of pairs, n=6:
-Each attempt is independent and therefore the probability of the events is calculated as:
[tex]P(A \ and \B )=P(A)\times P(B)\\\\P(6)=0.74\times0.74\times0.74\times0.74\times0.74\times0.74\\\\=0.1642[/tex]
#Hence, the probability of correctly identifying the 6 matches is 0.1642
*I have used the sample size of 6(due to conflicting info/question size).