Question

A druggist has two mixtures of a certain chemical and water, one containing 10% of the chemical and the other containing 40% of the chemical. How much of each mixture should he use to make 10 ounces that contain 25% of the chemical? 0.5 2.5 5

Answer 1

Answer:  5 pounds of each mixture should he use to make 10 ounces that contain 25% of the chemical.

Explanation:

$C_1M_1+C_2M_2=C_3M_3$

where,

$C_1$ and $C_2$ are the concentrations of mixing chemicals which are 10 % and 40 % respectively

$C_3$ is the concentration of resulting solution = 25 %

$M_1$ and $M_2$ are the mass of mixing chemicals which are x and (10-x) ounces respectively

$V_3$ is the mass of resulting solution = 10 ounces

$10\times x+40\times (10-x)=25\times 10$

$x=5$

(10-x)= (10-5) = 5 pounds

Thus 5 pounds of each mixture should he use to make 10 ounces that contain 25% of the chemical.