Answer:
The Required pressure for this situation is P= 735000Pa
Explanation:
In Determining the required pressure in this situation we use two equations
First one is
F = mg = (ρhA)g
And Second one is
P = [tex]F/A[/tex] = (ρhAg)/A Where P is pressure
We get
P = ρhg
since g = 9.8 m/s and h is given that is 75m and ρ = [tex]1000 kg/m^3[/tex]
so
P = (9.8 m/s)([tex]1000 kg/m^3[/tex])(75) we get
P = 735000 Pa