Explanation:
Hello! Remember you have to write complete questions in order to get good and exact answers. Here you haven't provided any figure, so I could help you providing my own triangle (isosceles triangle) which is shown below. We know that the area of a triangle is defined by:
[tex]A=\frac{bh}{2} \\ \\ \\ Where: \\ \\ A:Area \\ \\ b:base \\ \\ h:height \\ \\ \\ Finding \ h: \\ \\ 32=\frac{4h}{2} \\ \\ h=\frac{2\times 32}{4}=16units[/tex]
So our goal is to find x. Since this is an isosceles triangle, we can use Pythagorean Theorem, therefore:
[tex]x=\sqrt{h^2+(4/2)^2} \\ \\ x=\sqrt{16^2+2^2}=2\sqrt{65}[/tex]
Finally, the missing side are:
[tex]2\sqrt{65}units[/tex]
