Probability of getting sum of 9 on 3 throws of die = [tex]\frac{10}{64}[/tex]
Step-by-step explanation:
Step 1 :
Number of faces of the die = 4
Numbers on face of the die = 1,2,3,4
Number of times the die is thrown = 3
We need to compute the probability of getting a sum of 9 on 3 throws. (probability that the random variable X = 9)
Step 2 :
The 4 faced die is thrown 3 times , hence the total outcome would be 4³ = 64
Combinations which result in the sum of 9 are
3,3,3 - occurs in 1 way
4,2,3 - occurs in 6 ways (2,3,4 / 2,4,3 / 3,2,4 / 3,4,2 / 4,3,2 / 4,2,3)
4,4,1 - occurs in 3 ways( 1,4,4 / 4,4,1 /4,1,4)
Total favorable outcomes = 6+3+1 = 10
P(X=9) = [tex]\frac{total favorable outcome}{total outcome}[/tex] = [tex]\frac{10}{64}[/tex]
Step 3 :
Answer :
Probability of getting sum of 9 on 3 throws of die = [tex]\frac{10}{64}[/tex]
