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Ben

[tex]\huge\boxed{\text{Any line with a slope of 3}}[/tex]

To find a line perpendicular to a line with a given slope, you just need to find the opposite reciprocal of the slope.

We are given a slope of [tex]-\frac{1}{3}[/tex].

Start by multiplying it by [tex]-1[/tex]. This means that if it was a negative number, it would become positive, and vice versa.

[tex]-\frac{1}{3}*-1=\frac{1}{3}[/tex]

Now, flip the numerator and denominator. This is called finding the reciprocal.

[tex]\frac{1}{3}\longrightarrow\frac{3}{1}=\boxed{3}[/tex]

This means that any line with a slope of [tex]3[/tex] would be a correct answer.

Answer:

line EF

Finding Perpendicular Lines

On a coordinate plane, 4 lines are shown. Line A B has points (negative 3, 2) and (3, 0). E F has points (0, negative 3) and (2, 3). Line J K has points (negative 3, negative 4) and (3, negative 2). Line M N has points (negative 1, 4) and (2, negative 5).

Which line is perpendicular to a line that has a slope

of Negative one-third?

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