Respuesta :
[tex]\huge\boxed{\text{Any line with a slope of 3}}[/tex]
To find a line perpendicular to a line with a given slope, you just need to find the opposite reciprocal of the slope.
We are given a slope of [tex]-\frac{1}{3}[/tex].
Start by multiplying it by [tex]-1[/tex]. This means that if it was a negative number, it would become positive, and vice versa.
[tex]-\frac{1}{3}*-1=\frac{1}{3}[/tex]
Now, flip the numerator and denominator. This is called finding the reciprocal.
[tex]\frac{1}{3}\longrightarrow\frac{3}{1}=\boxed{3}[/tex]
This means that any line with a slope of [tex]3[/tex] would be a correct answer.
Answer:
line EF
Finding Perpendicular Lines
On a coordinate plane, 4 lines are shown. Line A B has points (negative 3, 2) and (3, 0). E F has points (0, negative 3) and (2, 3). Line J K has points (negative 3, negative 4) and (3, negative 2). Line M N has points (negative 1, 4) and (2, negative 5).
Which line is perpendicular to a line that has a slope
of Negative one-third?