Answer:
1.3m/s^2
Explanation:
Data obtained from the question include:
U (initial velocity) = 0m/s
V (final velocity) = 8.59 m/s
s (distance) = 28.4m
a (Acceleration) =?
Using the equation of motion (v^2 = u^2 + 2as), the acceleration can be obtain as follows:
v^2 = u^2 + 2as
(8.59) ^2 = 0 + 2 x a x 28.4
73.7881 = 56.8a
Divide both side by the coefficient of a i.e 56.8
a = 73.7881/56.8
a = 1.3m/s^2
Therefore, the acceleration of the bike is 1.3m/s^2
