Question

The probe shown below is sixty millimeters south of a wire. The induced field at that location is 1.20 G in the eastern direction. The Earth's magnetic field at the location is 0.50 G in the northern direction. How strong is the total magnetic field measured by the probe?

Answer 1

Answer:

Net magnetic field at that position is given as 1.3 G

Explanation:

As we know that the magnetic field due to wire at the given position is

$B_1 = 1.20 G$towards East

now magnetic field due to Earths field is given as

$B_2 = 0.50 G$ Towards North

so net magnetic field at the given position is vector sum of magnetic field due to these two fields

So it is given as

$B = \sqrt{B_1^2 + B_2^2}$

so we will have

$B = \sqrt{1.20^2 + 0.50^2}$

$B = 1.3 G$