Question

In ΔEFG, the measure of ∠G=90°, the measure of ∠F=53°, and GE = 7.9 feet. Find the length of FG to the nearest tenth of a foot.

Answer 1

Answer:

FG ≈ 6.0 ft

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan53° = $\frac{opposite}{adjacent}$ = $\frac{GE}{FG}$ = $\frac{7.9}{FG}$

Multiply both sides by FG

FG × tan53° = 7.9 ( divide both sides by tan53° )

FG = $\frac{7.9}{tan53}$ ≈ 6.0 ft