Answer:
The length of the third side of given triangle lies between 6.5 and 19.9.
Step-by-step explanation:
The law of cosine is as follows
[tex]c^{2} =a^{2}+b^{2}+2abcos\alpha[/tex]---------------1
⇒ a and b are the given sides of the triangle and c is the third side, and [tex]\alpha[/tex] is the angle between a and b .
In equation 1 , the maximum and minimum values of [tex]cos\alpha[/tex] are 1 and -1.
so the value of c lies in between
⇒ [tex]\sqrt{a^{2}+b^{2}-2ab }[/tex] and [tex]\sqrt{a^{2}+b^{2}+2ab }[/tex] = [tex]|a-b| and |a+b|[/tex]
Given a=13.2 and b=6.7 so the the side lies in between |13.2-6.7| and |13.2+6.7|
so the third side lies between 6.5 and 19.9