Question

A (c4h8) reacts with borane in thf followed by hydrogen peroxide in aqueous naoh to give b (c4h10o). treatment of b with aqueous chromic acid or cro3 in acetic acid gives butanoic acid, ch3ch2ch2cooh. draw the structure of


a. you do not have to consider stereochemistry. in cases where there is more than one answer, just draw one.

Answer 1

Answer:

1-Butene

Explanation:

In the final reaction, the $H_2CrO_4$ will oxidize the previous molecule to obtain the butanoic acid, therefore the previous molecule has to be primary alcohol: 1-Butanol. The $BH_3$/$H_2O_2$ reaction can produce antimarkonikov alcohols therefore the initial molecule has to be an alkene: the 1-Butene.

To further explanations see the attached image.