Question

A 0.10-kg object is traveling to the right (in the positive direction) with a speed of 3.0 m/s. After a 0.20 s collision, the object is traveling to the left at 3.0 m/s. What is the magnitude of the impulse (in N-s) acting on the object? The answer must be positive. (NEVER include units in the answer to a numerical question.)

Answer 1

Answer:

Explanation:

Impulse = change in momentum

= m v - mu , ( u is initial velocity and v is final )

0.1 [ 3 - ( - 3) ]

= 0.6

Answer 2

The magnitude of the impulse will be  0.6 N-s

What is an impulse ?

Impulse is a term that is used to describe or quantify the effect of force acting over time to change the momentum of an object.

impulse = change in momentum

mass (m) = 0.10 kg

u = +3 m/s

v = - 3 m/s

impulse = final momentum - initial momentum

             = m*v - m*u

            = m*( v-u )

             = 0.10 * (-3 -3 )

             = - 0.6 N-s

The magnitude of the impulse will be  0.6 N-s

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