Answer:
Therefore the maximum revenue is $5,000 and 100 units should be manufactured to obtain the maximum revenue.
Explanation:
Given function is
r(x) = 100x- 0.5 x²
where the revenue r(x) is in dollar and no. unit is x.
We know that if function
y = ax²+bx+c.
Then we get the maximum value of y when [tex]x= -\frac b{2a}[/tex]
Here a= -0.5 , b = 100 and c=0.
Therefore,
[tex]x=-\frac{100}{2.(-0.5)} =100[/tex]
Therefore we get maximum revenue when x=100.
∴ r(100) = 100.100- 0.5(100)²
=$5000
Therefore the maximum revenue is $5,000 and 100 units should be manufactured to obtain the maximum revenue.