Question

car is being driven at a rate of 40 ft/sec when the brakes are applied. The car decelerates at a constant rate of 12 ft/sec2. How long before the car stops? Round your answer to one decimal place.

Answer 1

Answer:

66.7 feet

Step-by-step explanation:

v² = u² + 2as

0² = 40² + 2(-12)(so

1600 = 24s

s = 66⅔ or 66.7

Answer 2

Using the motion equation, the distance traveled by the car comes to rest would be 66.67 metres.

Using the relation :

• v² = u² - 2as
• Since the car is decelerating
• Final velocity, v = 0

Hence, we have ;

0² = 40² - 2(12)(s)

0 = 1600 - 24s

24s = 1600

Divide both sides by 24

s = 1600/24

s = 66.67 meters.

Hence, the car would travel a distance of 66.67 meters before stopping.

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