Question

Three parcels weigh 2 pounds two parcels weigh the same the lightest weight is 5/8 pound lighter than the heaviest weight how much do each of the parcels weigh

Answer 1

Answer:

Two parcels weigh $\frac{11}{12}$ lb and the heaviest parcel weigh $1\frac{1}{12}$ lb.

Step-by-step explanation:

Let the weight of two parcels which are equal in weight = x lb

and the weight of the heaviest weight parcel = y lb

From the statement of the question,

"Three parcels weigh 2 pounds".

x + x + y = 2

2x + y = 2 -------(1)

"The lightest wight is $\frac{5}{8}$ pound lighter then the heaviest".

$x=y-\frac{5}{8}$

$x-y=-\frac{5}{8}$ --------(2)

Now we add equation (1) and equation (2)

(2x + y) + (x - y) = 2 - $\frac{5}{8}$

3x = $\frac{16-5}{8}$

3x = $\frac{11}{8}$

x = $\frac{11}{24}$ lb

from equation (1),

$2(\frac{11}{24})+y=2$

y = 2 - $\frac{11}{12}$

y = $\frac{13}{12}$ lb ≈ $1\frac{1}{12}$

Therefore, two parcels weigh $\frac{11}{12}$ lb and the heaviest parcel weigh $1\frac{1}{12}$ lb.