Respuesta :

Answer:

2.87 liter.

Explanation:

Given:

Initially volume of balloon = 4.3 liter

Initially temperature of balloon = 350 K

Question asked:

What volume will the gas in the balloon occupy at 250 K ?

Solution:

By using:

[tex]Pv =nRT[/tex]

Assuming pressure as constant,

V∝ T

Now, let  K is the constant.

V = KT

Let initial volume of balloon , [tex]V_{1}[/tex] = 4.3 liter

1000 liter = 1 meter cube

1 liter = [tex]\frac{1}{1000} m^{3} = 10^{-3} m^{3[/tex]

4.3 liter = [tex]4.3\times10^{-3}=4.3\times10^{-3} m^{3}[/tex]

And initial temperature of balloon, [tex]T_{1}[/tex] = 350 K

Let the final volume of balloon is [tex]V_{2}[/tex]

And as given, final temperature of balloon, [tex]T_{2}[/tex] is 250 K

Now, [tex]V_{1} = KT_{1}[/tex]

[tex]4.3\times10^{-3}=K\times350\ (equation\ 1 )[/tex]

[tex]V_{2} = KT_{2}[/tex]

[tex]=K\times250\ (equation 2)[/tex]

Dividing equation 1 and 2,

[tex]\frac{4.3\times10^{-3}}{V_{2} } =\frac{K\times350}{K\times250}[/tex]

K cancelled by K.

By cross multiplication:

[tex]350V_{2} =4.3\times10^{-3} \times250\\V_{2} =\frac{ 4.3\times10^{-3} \times250\\}{350} \\ = \frac{1075\times10^{-3}}{350} \\ =2.87\times10^{-3}m^{3}[/tex]

Now, convert it into liter with the help of calculation done above,

[tex]2.87\times10^{-3} \times1000\\2.87\times10^{-3} \times10^{3} \\2.87\ liter[/tex]

Therefore, volume of the gas in the balloon at 250 K will be  2.87 liter.

The volume of the gas in the balloon at 250K will be 3.07L.

Ideal gas equation:

It is given as,   [tex]PV=nRT[/tex]

Where P is pressure, V is volume , T is temperature and n is number of moles of gas.

Assuming pressure is constant,

Then, Volume is directly proportional to temperature.

                        V∝ T

Given that, initial volume and temperature is [tex]V_{1}=4.3L,T_{1}=350K[/tex]

and [tex]T_{2}=250K[/tex], we have to calculate [tex]V_{2}[/tex].

           [tex]\frac{V_{1}}{V_{2}} =\frac{T_{1}}{T_{2}} \\\\\frac{4.3}{V_{2}}=\frac{350}{250}\\ \\ V_{2}=\frac{4.3*250}{350}=3.07L[/tex]

The volume of the gas in the balloon at 250K will be 3.07L.

Learn more about the ideal gas law here:

https://brainly.com/question/1056445