Question

6. During a single day at radio station WMZH, the probability that a particular song is played is

0.41. What is the probability that this song will be played on exactly 0 days out of 4 days?

Answer 1

Answer:

Step-by-step explanation:

Probability that a particular song p = 0.41

q = 1 - p = 1 - .41 = .59

n = 4 , r  = 0

Probability that this song will be played on exactly 0 days =  $(_{r}^{n}\textrm{})$$p^{r} q^{n-r}$  

= $(_{0}^{4}\textrm{})$$(.41)^{0} (.59)^{4}$

= 4 x 1 x .1211 = .484