Answer:
In second case voltage will be 2.986 volt
Explanation:
In first case we have given frequency f = 3 kHz = 3000 Hz
Voltage v = 2 volt
Current i = 1 mA
So capaitive reactance [tex]X_C=\frac{V}{i}=\frac{2}{31\times 10^{-3}}=64.5161ohm[/tex]
[tex]X_C=\frac{1}{\omega C}[/tex]
So [tex]64.5161=\frac{1}{2\times 3.14\times 3000\times C}[/tex]
[tex]C=8.22\times 10^{-7}F[/tex]
In second case frequency f =4.8 kHz = 4800 Hz
Capacitive reactance [tex]X_C=\frac{1}{\omega C}=\frac{1}{2\times 3.14\times 4800\times 8.22\times 10^{-7}}=40.3577ohm[/tex]
Current i = 74 mA
So voltage [tex]V=iX_C=74\times 10^{-3}\times 40.3577=2.986volt[/tex]