Question

An l-c circuit has an inductance of 0.450 h and a capacitance of 0.200 nf . during the current oscillations, the maximum current in the inductor is 1.40


a. part a what is the maximum energy e max stored in the capacitor at any time during the current oscillations?

Answer 1

Answer:

0.441 J

Explanation:

The maximum energy stored in the capacitor = maximum energy stored in inductor, E = 1/2Li². where L = inductance = 0.450 H and i = current = 1.40 A

E = 1/2Li² = 1/2 × 0.45 × 1.40² = 0.441 J

Answer 2

The maximum energy stored in capacitor is; 0.441 J

We are given;

Inductance; L = 0.45 H

Capacitance; C = 0.2 nF

Current; I = 1.4 A

Now, there is no resistance in the circuit and no energy is lost through heating. Thus, we can say that;

Maximum energy stored in capacitor = maximum energy stored in the inductor.

Formula for E_max for inductor is;

E_max = ½LI²

E_max = ½ × 0.45 × 1.4

E_max = 0.441 J

Therefore in conclusion, Maximum energy stored in capacitor is 0.441 J

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