Question

A box contains ten cards labeled Q,R,S,T,U,V,W,X,Y, and Z. One card will be randomly chosen. What is the probability of choosing a letter from U to Z?

Answer 1

Answer:

Therefore,

The probability of choosing a letter from U to Z is

$P(A)=0.6$

Step-by-step explanation:

A box contains ten cards labeled Q,R,S,T,U,V,W,X,Y, and Z. One card will be randomly chosen.

Given

Let "S" be the sample space of the Experiment for a card choose

S = { Q, R, S, T, U, V, W, X, Y, Z }

n(S) = 10

Let A be the event of getting a letter U to Z,

A = { U, V, W, X, Y, Z }

n(A) = 6

To Find:

P(A) = ?

Solution:

Now Probability is given as

$P(A)=\dfrac{\textrm{ Favorable Outcomes}}{Total Number of Outcomes}=\dfrac{n(A)}{n(S)}$

Substituting the values we get

$P(A)=\dfrac{6}{10}=\dfrac{3}{5}=0.6$

Therefore,

The probability of choosing a letter from U to Z is

$P(A)=0.6$