Respuesta :
The question is incomplete, complete question is :
A chemist adds 55.0 mL of a 1.1 M barium acetate solution to a flask. Calculate the mass in grams of barium acetate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.
Answer:
15.4 grams is the mass of barium acetate the chemist has added to the flask.
Explanation:
[tex]Molarity=\frac{\text{Mass of substance}}{\text{Molar mass of substance}\times \text{Volume of solution(L)}}[/tex]
Mass of barium acetate = x
Molar mass of barium acetate = 255 g/mol
Volume of solution = 55.0 mL = 0.055 L ( 1 mL = 0.001 L)
Molarity of the barium acetate solution = 1.1 M
[tex]1.1 M=\frac{x}{255 g/mol\times 0.055 L}[/tex]
[tex]x=1.1 M\times 255 g/mol\times 0.055 L=15.43 g\approx 15.4 g[/tex]
15.4 grams is the mass of barium acetate the chemist has added to the flask.
