Answer:
The correct answer is: [tex]( x + 4) ^ {2} + (y - 3) ^ {2} \leq 9[/tex]
Step-by-step explanation:
The airport is located at the point (-4 , 3). Thus we can consider the center of the circle to be this particular point.
Since the noise can be heard till 3 miles away, this implies we can consider the radius of the circle to be 3.
We all know the general equation of circle with center at ([tex]\alpha[/tex] , [tex]\beta[/tex]) with radius r is given by:
[tex](x - \alpha ) ^{2} + (y - \beta )^{2} = r^{2}[/tex]
Here the value of [tex]\alpha[/tex] is (-4) ; value of [tex]\beta[/tex] is 3 ; and value of r is 3.
Now since the noise of landing and taking off of the planes would be within the circle, hence we use less than equal to ([tex]\leq[/tex]) sign instead of equal to sign.
Thus the general equation of noise of the planes can be given by the inequality
[tex]( x - (- 4)) ^ {2} + (y - 3) ^ {2} \leq 3^{2}\\= ( x + 4) ^ {2} + (y - 3) ^ {2} \leq 3^{2}[/tex]