An airport is located at the point (-4, 3). The noise of planes landing and taking off can be heard up to 3 miles away. Write the inequality of a circle that represents the situation

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Answer:

The correct answer is: [tex]( x + 4) ^ {2} + (y - 3) ^ {2} \leq 9[/tex]

Step-by-step explanation:

The airport is located at the point (-4 , 3). Thus we can consider the center of the circle to be this particular point.

Since the noise can be heard till 3 miles away, this implies we can consider the radius of the circle to be 3.

We all know the general equation of circle with center at ([tex]\alpha[/tex] , [tex]\beta[/tex]) with radius r is given by:

[tex](x - \alpha ) ^{2} + (y - \beta )^{2} = r^{2}[/tex]

Here the value of [tex]\alpha[/tex] is (-4) ; value of [tex]\beta[/tex] is 3 ; and value of r is 3.

Now since the noise of landing and taking off of the planes would be within the circle, hence we use less than equal to ([tex]\leq[/tex]) sign instead of equal to sign.

Thus the general equation of noise of the planes can be given by the inequality

[tex]( x - (- 4)) ^ {2} + (y - 3) ^ {2} \leq 3^{2}\\= ( x + 4) ^ {2} + (y - 3) ^ {2} \leq 3^{2}[/tex]

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