Question

A uniform linear charge density of 4.0nC/m is distributed along the entire x axis. Consider a spherical(radius = 5.0 cm) surface centered on the origin. Determine theelectric flux through this surface.


1. 79 N · m2/C

2. 45 N · m2/C (what i think itis)

3. 68 N · m2/C

4. 62 N · m2/C

5. 23 N · m2/C (what the reply said itwas)

Answer 1

Answer:

Ф = 45 N m² / C

Explanation:

For this exercise we use Gauss's law

        Ф = E .dA = qint / ε₀

        A = 4π r²

        Ф = E 4π r² = qint /ε₀  

Since the charge is along the x axis the linear charge density

         λ = q / x

         q = λ x

The charge inside the Gaussian surface is the charge on the line from x = -5 cm to x = 5 cm, so x_total = 10 cm

        Φ = λ x_total / ε₀  

Let's calculate

       Φ = 4.0 10⁻⁹ 0.10 / 8.85 10⁻¹²

       Ф = 45 N m² / C

Answer 2

The electric flux through the surface of the sphere is 45.1 m.

The given parameters:

• Linear charge density, σ = 4 nC/m
• Radius of the sphere, r = 5.0 cm

The electric flux through the surface of the sphere is calculated as follows;

$\Phi = \frac{Q _{encl}}{\varepsilon _0} \\\\ \Phi = \frac{\sigma \times 2r}{\varepsilon _0} \\\\ \Phi = \frac{4 \times 10^{-9} \times 2 \times 0.05}{8.85 \times 10^{-12} } \\\\ \Phi = 45.1 \ m^2 /C$

Thus, the electric flux through the surface of the sphere is 45.1 m²/C.

Learn more about electric flux here: https://brainly.com/question/26289097