Respuesta :
Answer:
[tex]\mu_p=2000\\\\\sigma_p^2=3600[/tex]
Step-by-step explanation:
Let X be the number of units produced, and P be the cost of production.
#Given that [tex]\mu_x=500, \sigma_x^2=900[/tex]
Cost of production can be calculated as:
[tex]P=1000+2X[/tex]
#Mean of the total cost is calculated as;
[tex]\mu_p=1000+2\mu_x\\\\=1000+2(500)\\\\=2000[/tex]
Hence, the mean cost of production is $2,000
#Variance of the total cost is calculated as;
[tex]\sigma_p^2=2^2\sigma_x^2\\\\=2^\times 900\\\\=3600[/tex]
Hence, the variancecost of production is $3,600
The total cost mean of the cost of production is $2000 and the variance is $3600.
From the given information, the number of samples (n) is given as 500. Therefore, the total cost will be:
= 1000 + 2n
= 1000 + 2(500)
= 1000 + 1000
= 2000.
Since variance = 900, the standard deviation will be:
= ✓900 = 30
The standard deviation for the total cost will be:
= 2n = 2 × 30 = 60
Variance will be = 60² = 3600
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