Answer:
[OH⁻] = 1 × 10⁻¹¹ mol/dm³
Explanation:
Since the hydronium ion concentration of the gastric fluid is [H₃O]⁺ = 1.0 × 10⁻².
The pH at this point is pH = -log₁₀[H₃O]⁺ = -log₁₀[1.0 × 10⁻²] = 2
When milk of magnesia is added, the pH increases by one unit, so the new pH is 1 + 2 = 3
Since pH + pOH = 14, then pOH = 14 - pH = 14 - 3 = 11
The hydroxide ion concentration of the fluid is gotten from
pOH = -log₁₀[OH⁻]
11 = -log₁₀[OH⁻]
-11 = log₁₀[OH⁻]
taking antilog
[OH⁻] = 1 × 10⁻¹¹ mol/dm³
Answer:
1 × 10^-11 units.
Explanation:
Given:
[H+] = 1 × 10^-2
pH = - log [H+]
= -log [1 × 10^-2]
= 2
The question further said, "which raises the ph of the fluid by one unit"
pH(new) = 2 + 1
= 3
pH + pOH = 14
pOH = 14 - 3
= 11
pOH = - log [OH-]
[OH-] = 10^-11
= 1 × 10^-11 units
