Question

an asteroid whose mass is 2.0 x 10^-4 times the mass of earth revolves in a circular orbit around the sun at a distance that is twice the earth's distance from the sun calculate the period of revolution of the asteroid in years

Answer 1

Answer:

0.0002

Explanation:

First you have to solve exponents first, so you solve 10 to the power of negative 4 which is 0.0001 and now you have 2.0x0.0001 and that equals 0.0002