Pressure is 5.7 atm
Explanation:
P1 = Standard pressure = 1 atm
P2 = ?
V1 = Volume = 10L
V2= 2.4L
T1 = 0°C + 273 K = 273 K
T2 = 100°C + 273 K = 373 K
We have to find the pressure of the gas, by using the gas formula as,
[tex]$\frac{P 1 V 1}{T 1}=\frac{P 2 V 2}{T 2}[/tex]
P2 can be found by rewriting the above expression as,
[tex]$P 2=\frac{P 1 \times V 1 \times T 2}{T 1 \times V 2}[/tex]
Plugin the above values as,
[tex]$P 2=\frac{1 \text {atm} \times 10 L \times 373 \mathrm{K}}{273 \mathrm{K} \times 2.4 \mathrm{L}}=5.7 \text { atm }[/tex]