Question

6 miles
10 miles
Joe is trying to determine the shortest route he can take to get back home. He is currently at point A and can only travel the
boundary lines to get to point D. He knows that segment AD bisects LA
Which route is shortest and by how much?

Answer 1

Answer:

C) Going from A to C to D and it is shorter by 3 miles.

Step-by-step explanation:

Angles  

AB is 6 miles

BD is _12__ miles

AC is 5 miles

CD is 10 miles

First you need to find BD, so AB times CD. 6(10) = 60. then divide 60 with AC. 60/5 = 12. So  BD = 12.  

Now add  

AB and BD,  

{ 6+ 12 = 18} ABD = 18

Now add  

AC and CD

{ 5 + 10 = 15 } ACD = 15

18 - 15 = 3  

So ACD is 3 miles shorter then ABD.

Got right on the test