Respuesta :
[tex]A) -27a^3 b^6 + 8a^9 b^{12}\\D) 27a^3 b^6 + 8a^9 b^{12}[/tex]
Step-by-step explanation:
Here, the given expressions are:
[tex]A) -27a^3 b^6 + 8a^9 b^{12}\\= (-3)^3(a^3)(b^2)^3 + (2)^3(a^3)3(b^4)^3\\= (-3ab^2)^3 +(2a^3b^4)^3[/tex]
So, the above expression is "sum of cubes".
[tex]B) -9a^3 b^6 + a^9 b^{10}\\[/tex]
But (-9) can not be expressed as a Perfect cube root.
So, the above expression is not "sum of cubes".
[tex]C) 9a^3 b^6 + 8a^9 b^{12}\\[/tex]
But (9) can not be expressed as a Perfect cube root.
So, the above expression is not "sum of cubes".
[tex]D) 27a^3 b^6 + 8a^9 b^{12}\\\\= (3)^3a^3(b^2)^3 + (2)^3(a^3)^3(b^4)^3\\= (3ab^2)^3+ (2a^3b^4)^3[/tex]
So, the above expression is "sum of cubes".