Question

The perimeter of a triangle is 65 meters. The second side is 5 meters less than the first side The third side is 7
meters more than the first side. What is the length of each side?​

Answer 1

Answer:

x=21

y=16

z=28

Step-by-step explanation:

Let

The first side=x

The second side =y

The third side=z

The rest is in the attached file

Answer 2

Answer:

First side (x)$=21m$

Second side$=x-5=21-5=16m$

Third side$= x+7=21+7=28m$

Step-by-step explanation:

Perimeter of the triangle= Sum of all the three sides

Let the First side be $'x'$

Then, Second side $=x-5$

Third side= $x+7$

Perimeter$=65 m$

Perimeter of the triangle= First side + Second side + Third side

      $65=x+(x-5)+(x+7)\\\\65=x+x+x-5+7\\\\65=3x+2\\\\3x=65-2\\\\3x=63\\\\x=63/3\\\\x=21 m$

First side (x)$=21m$

Second side$=x-5=21-5=16m$

Third side$= x+7=21+7=28m$