Question

The length and width of a rectangle or both doubled what is the ratio of the area of the larger rectangle to the area of the smaller rectangle

Answer 1

ratio of the area of the larger rectangle to the area of the smaller rectangle is 4:1 .

Step-by-step explanation:

Here we have ,The length and width of a rectangle or both doubled  . We need to find that  the ratio of the area of the larger rectangle to the area of the smaller rectangle . Let's solve this:

Area of smaller rectangle:

Let length and breadth are x & y respectively

⇒ $Area_1 = length(width)$

⇒ $Area _1= xy$

Area of larger rectangle:

Let length and breadth are 2x & 2y( according to question sides are doubled) respectively ,

⇒ $Area_2 = length(width)$

⇒ $Area_2 = 2x(2y)$

⇒ $Area_2 = 4xy$

⇒ $Area_2 = 4Area_1$

⇒ $\frac{Area_2}{Area_1} = \frac{4}{1}$

Therefore , ratio of the area of the larger rectangle to the area of the smaller rectangle is 4:1 .