Answer:
Torque = 0.47 Nm
Explanation:
Torque = BIAsin∅
Since the plane is parallel to the magnetic field, ∅ = 90⁰
sin 90 = 1
Magnetic field, B = 0.30 T
current, I = 2.0 A
Radius, R = 0.50 m
A = πR²
A = π(0.5)² = 0.785 m²
Torque = 0.3 * 2 * 0.785
Torque = 0.47 Nm
Answer:
The magnetic torque when the plane of the loop is parallel to the magnetic field is zero.
Explanation:
Given;
radius of wire, r = 0.50 m
strength of magnetic field, B = 0.3 T
current in the wire, I = 2.0 A
Dipole moment, μ = I x A
where;
A is the area of the circular loop = πr² = π(0.5)² = 0.7855 m²
Dipole moment, μ = 2A x 0.7855m² = 1.571 Am²
magnetic torque, τ = μBsinθ
when the plane of the loop is parallel to the magnetic field, θ = 0
τ = 1.571 Am² x 0.3sin0
τ = 0
Therefore, the magnetic torque when the plane of the loop is parallel to the magnetic field is zero.
