Question

A bucket filled with water has a mass of 53 kg and is hanging from a rope that is wound around a 0.05 m radius stationary cylinder. If the cylinder does not rotate and the bucket hangs straight down, what is the magnitude of the torque the bucket produces around the center of the cylinder

Answer 1

Answer:

26 Nm

Explanation:

we use the formula for torque:

$T=r*F$

where $r$ is the radius and $F$ is the force applied.

The force that the bucket exerts on the cylinder is equal to the weight of the bucket $w=m*g$  (since the bucket is not moving this is the only force present), where m is the mass and g is the acceleration due to gravity.

So the force is:

$F=w\\F=m*g$

And substituting this in the equation for the torque:

$T=r*m*g$

substituting the values we know:

$r=0.05m\\m=53kg\\g=9.81m/s$

the result is:

$T=(0.05m)*(53kg)*(9.81m/s^2)\\T=26Nm$